Optimal. Leaf size=250 \[ \frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}+\frac{2 (2 c d-b e) (e f-d g) \sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{e^2 \sqrt{d+e x}}-\frac{2 (2 c d-b e)^{3/2} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{\sqrt{d+e x} \sqrt{2 c d-b e}}\right )}{e^2}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}} \]
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Rubi [A] time = 0.44881, antiderivative size = 250, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 46, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.087, Rules used = {794, 664, 660, 208} \[ \frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}+\frac{2 (2 c d-b e) (e f-d g) \sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{e^2 \sqrt{d+e x}}-\frac{2 (2 c d-b e)^{3/2} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{\sqrt{d+e x} \sqrt{2 c d-b e}}\right )}{e^2}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 794
Rule 664
Rule 660
Rule 208
Rubi steps
\begin{align*} \int \frac{(f+g x) \left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2}}{(d+e x)^{5/2}} \, dx &=-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}}-\frac{\left (2 \left (\frac{5}{2} e \left (-2 c e^2 f+b e^2 g\right )-\frac{5}{2} \left (-c e^3 f+\left (-c d e^2+b e^3\right ) g\right )\right )\right ) \int \frac{\left (c d^2-b d e-b e^2 x-c e^2 x^2\right )^{3/2}}{(d+e x)^{5/2}} \, dx}{5 c e^3}\\ &=\frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}}+\frac{((2 c d-b e) (e f-d g)) \int \frac{\sqrt{c d^2-b d e-b e^2 x-c e^2 x^2}}{(d+e x)^{3/2}} \, dx}{e}\\ &=\frac{2 (2 c d-b e) (e f-d g) \sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{e^2 \sqrt{d+e x}}+\frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}}+\frac{\left ((2 c d-b e)^2 (e f-d g)\right ) \int \frac{1}{\sqrt{d+e x} \sqrt{c d^2-b d e-b e^2 x-c e^2 x^2}} \, dx}{e}\\ &=\frac{2 (2 c d-b e) (e f-d g) \sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{e^2 \sqrt{d+e x}}+\frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}}+\left (2 (2 c d-b e)^2 (e f-d g)\right ) \operatorname{Subst}\left (\int \frac{1}{-2 c d e^2+b e^3+e^2 x^2} \, dx,x,\frac{\sqrt{c d^2-b d e-b e^2 x-c e^2 x^2}}{\sqrt{d+e x}}\right )\\ &=\frac{2 (2 c d-b e) (e f-d g) \sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{e^2 \sqrt{d+e x}}+\frac{2 (e f-d g) \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{3/2}}{3 e^2 (d+e x)^{3/2}}-\frac{2 g \left (d (c d-b e)-b e^2 x-c e^2 x^2\right )^{5/2}}{5 c e^2 (d+e x)^{5/2}}-\frac{2 (2 c d-b e)^{3/2} (e f-d g) \tanh ^{-1}\left (\frac{\sqrt{d (c d-b e)-b e^2 x-c e^2 x^2}}{\sqrt{2 c d-b e} \sqrt{d+e x}}\right )}{e^2}\\ \end{align*}
Mathematica [A] time = 0.295091, size = 199, normalized size = 0.8 \[ -\frac{2 \sqrt{d+e x} \sqrt{c (d-e x)-b e} \left (\sqrt{c (d-e x)-b e} \left (3 b^2 e^2 g+2 b c e (-13 d g+10 e f+3 e g x)+c^2 \left (38 d^2 g-d e (35 f+11 g x)+e^2 x (5 f+3 g x)\right )\right )-15 c (2 c d-b e)^{3/2} (d g-e f) \tanh ^{-1}\left (\frac{\sqrt{-b e+c d-c e x}}{\sqrt{2 c d-b e}}\right )\right )}{15 c e^2 \sqrt{(d+e x) (c (d-e x)-b e)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.02, size = 601, normalized size = 2.4 \begin{align*} -{\frac{2}{15\,c{e}^{2}}\sqrt{-c{e}^{2}{x}^{2}-b{e}^{2}x-bde+c{d}^{2}} \left ( 3\,{x}^{2}{c}^{2}{e}^{2}g\sqrt{be-2\,cd}\sqrt{-cex-be+cd}+15\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ){b}^{2}cd{e}^{2}g-15\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ){b}^{2}c{e}^{3}f-60\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ) b{c}^{2}{d}^{2}eg+60\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ) b{c}^{2}d{e}^{2}f+60\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ){c}^{3}{d}^{3}g-60\,\arctan \left ({\frac{\sqrt{-cex-be+cd}}{\sqrt{be-2\,cd}}} \right ){c}^{3}{d}^{2}ef+6\,xbc{e}^{2}g\sqrt{be-2\,cd}\sqrt{-cex-be+cd}-11\,x{c}^{2}deg\sqrt{be-2\,cd}\sqrt{-cex-be+cd}+5\,x{c}^{2}{e}^{2}f\sqrt{be-2\,cd}\sqrt{-cex-be+cd}+3\,{b}^{2}{e}^{2}g\sqrt{be-2\,cd}\sqrt{-cex-be+cd}-26\,bcdeg\sqrt{-cex-be+cd}\sqrt{be-2\,cd}+20\,bc{e}^{2}f\sqrt{-cex-be+cd}\sqrt{be-2\,cd}+38\,{c}^{2}{d}^{2}g\sqrt{-cex-be+cd}\sqrt{be-2\,cd}-35\,{c}^{2}def\sqrt{-cex-be+cd}\sqrt{be-2\,cd} \right ){\frac{1}{\sqrt{ex+d}}}{\frac{1}{\sqrt{-cex-be+cd}}}{\frac{1}{\sqrt{be-2\,cd}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e\right )}^{\frac{3}{2}}{\left (g x + f\right )}}{{\left (e x + d\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.48639, size = 1384, normalized size = 5.54 \begin{align*} \left [\frac{15 \, \sqrt{2 \, c d - b e}{\left ({\left (2 \, c^{2} d^{2} e - b c d e^{2}\right )} f -{\left (2 \, c^{2} d^{3} - b c d^{2} e\right )} g +{\left ({\left (2 \, c^{2} d e^{2} - b c e^{3}\right )} f -{\left (2 \, c^{2} d^{2} e - b c d e^{2}\right )} g\right )} x\right )} \log \left (-\frac{c e^{2} x^{2} - 3 \, c d^{2} + 2 \, b d e - 2 \,{\left (c d e - b e^{2}\right )} x + 2 \, \sqrt{-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e} \sqrt{2 \, c d - b e} \sqrt{e x + d}}{e^{2} x^{2} + 2 \, d e x + d^{2}}\right ) - 2 \,{\left (3 \, c^{2} e^{2} g x^{2} - 5 \,{\left (7 \, c^{2} d e - 4 \, b c e^{2}\right )} f +{\left (38 \, c^{2} d^{2} - 26 \, b c d e + 3 \, b^{2} e^{2}\right )} g +{\left (5 \, c^{2} e^{2} f -{\left (11 \, c^{2} d e - 6 \, b c e^{2}\right )} g\right )} x\right )} \sqrt{-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e} \sqrt{e x + d}}{15 \,{\left (c e^{3} x + c d e^{2}\right )}}, -\frac{2 \,{\left (15 \, \sqrt{-2 \, c d + b e}{\left ({\left (2 \, c^{2} d^{2} e - b c d e^{2}\right )} f -{\left (2 \, c^{2} d^{3} - b c d^{2} e\right )} g +{\left ({\left (2 \, c^{2} d e^{2} - b c e^{3}\right )} f -{\left (2 \, c^{2} d^{2} e - b c d e^{2}\right )} g\right )} x\right )} \arctan \left (\frac{\sqrt{-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e} \sqrt{-2 \, c d + b e} \sqrt{e x + d}}{c e^{2} x^{2} + b e^{2} x - c d^{2} + b d e}\right ) +{\left (3 \, c^{2} e^{2} g x^{2} - 5 \,{\left (7 \, c^{2} d e - 4 \, b c e^{2}\right )} f +{\left (38 \, c^{2} d^{2} - 26 \, b c d e + 3 \, b^{2} e^{2}\right )} g +{\left (5 \, c^{2} e^{2} f -{\left (11 \, c^{2} d e - 6 \, b c e^{2}\right )} g\right )} x\right )} \sqrt{-c e^{2} x^{2} - b e^{2} x + c d^{2} - b d e} \sqrt{e x + d}\right )}}{15 \,{\left (c e^{3} x + c d e^{2}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (- \left (d + e x\right ) \left (b e - c d + c e x\right )\right )^{\frac{3}{2}} \left (f + g x\right )}{\left (d + e x\right )^{\frac{5}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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